Intro:
The purpose
of this lab is to find the resistance of cables attached from a battery to a
load. In the following figure.
The cables are represented by a resistors, which
we will call RCable tot.
Experiment:
To find the
load resistance of a load supplied with 12V and consumes .044W we get
RLoad=V^2/P=12^2/.144=1000
ohms
Data
RLoad = 998 ohms
Vload=11.00V
IBatt = 11.45mA
RCable tot = 98 ohms
Analysis;
For a .8 Ahr
the device will last
.8Ahr*.01145A=70.0 hours
The efficiency can be calculated by Pout/(Pout + PLost)
Pout = V^2/R=11^2/998
PLost = I^2V = (.01145)*98=.01284
Pout/(Pout + PLost)*100=90.41%
Given a resistance of AWG #30 of .345ohms/m the maximum distance is
98ohms/(.345omhs/m)=284.0 m
An AWG# 28 that can keep a 20mA 5V signal is 1576ft long.
Sending a 48 volt signal at 10 amps that will deliver 36 volts to a sub 60ft below needs a resistance of .02 ohms per feet. ohms. AWG#22 is .0190 ohms per feet.
An AWG# 28 that can keep a 20mA 5V signal is 1576ft long.
Sending a 48 volt signal at 10 amps that will deliver 36 volts to a sub 60ft below needs a resistance of .02 ohms per feet. ohms. AWG#22 is .0190 ohms per feet.
No comments:
Post a Comment